-3x^2-10x-7=0

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Solution for -3x^2-10x-7=0 equation:



-3x^2-10x-7=0
a = -3; b = -10; c = -7;
Δ = b2-4ac
Δ = -102-4·(-3)·(-7)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4}{2*-3}=\frac{6}{-6} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4}{2*-3}=\frac{14}{-6} =-2+1/3 $

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